NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.2
Here at MentorAtHome, we provide NCERT Solution for class 6 maths chapter 2 Whole Numbers we study numbers, number lines, addition, multiplication and subtraction using suitable properties like distributive, commutative etc. NCERT solution for class 6 maths chapter 2 help to make your calculation fast.
NCERT solution for class 6 maths chapter 2 Ex 2.2 : whole numbers
In NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.2, we study about Properties of whole numbers are:- Addition and multiplication of any 2 whole numbers give a whole number and Subtraction and division of any 2 whole numbers may or may not give a whole number. NCERT Class 6 maths solutions ex 2.2 are designed in a simple way that’s students easily understand.
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Here we provide NCERT solutions of class 6 maths chapter 2 exercise 2.2. If you want to see solutions of other chapters you can check them by the above links.
exercise 2.2
NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.2
Class 6 Maths exercise 2.2 solutions Question 1
Q.1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647
Ans:-
(a) 837 + 208 + 363 = (837 + 363) + 208
= 1200 + 208 = 1408
(b) 1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100 = 4600
Class 6 exercise 2.2 solutions question 2
Q.2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
Ans:-
2 x 1768 x 50 = (2 x 50) x 1768 = 176800
(b) 4 × 166 × 25
Ans:-
4 x 166 x 25 = 166 x (25 x 4) = 166 x 100 = 16600
(c) 8 × 291 × 125
Ans:-
8 x 291 x 125 = (8 x 125) x 291 = 1000 x 291 = 291000
(d) 625 × 279 × 16
Ans:-
625 x 279 x 16 = (625 x 16) x 279 = 10000 x 279 = 2790000
(e) 285 × 5 × 60
Ans:-
285 x 5 x 60 = 285 x (5 x 60) = 285 x 300 = (300 – 15)x 300 = 300 x 300 – 15 x 300 = 90000 – 4500 = 85500
(f) 125 × 40 × 8 × 25
Ans:-
125 x 40 x 8 x 25 = (125 x 8) x (40 x 25) = 1000 X 1000 = 1000000
Class 6 exercise 2.2 solutions question 3
Q.3. Find the value of the following:
(a) 297 × 17 + 297 × 3
Ans:-
297 x 17 x 297 x 3 = 297 x (17 + 3)
= 297 x 20 = 297 x 2 x 10
= 594 x 10 = 5940
(b) 54279 × 92 + 8 × 54279
Ans:-
54279 x 92 + 8 x 54279 = 54279 x (92 + 8)
= 54279 x 100 = 5427900
(c) 81265 × 169 – 81265 × 69
Ans:-
81265 x 169 – 81265 x 69
= 81265 x (169 – 69)
= 81265 x 100 = 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
Ans:-
3845 x 5 x 782 + 769 x 25 x 218 = 3845 x 5 x 782 + 769 x 5 x 5 x 218
= 3845 x 5 x 782 + (769 x 5) x 5 x 218
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 3845 x 5 x 1000
= 19225 x 1000
= 19225000
NCERT solution for class 6 maths chapter 2 Ex 2.2 question 4
Q.4. Find the product using suitable properties.
(a) 738 × 103
Ans:-
738 x 103 = 738 x (100 + 3)
= 738 x 100 + 738 x 3 [Using distributive property]
= 73800 + 2214 = 76014
(b) 854 × 102
Ans:-
854 x 102 = 854 x (100 + 2)
= 854 x 100 + 854 x 2 [Using distributive property]
= 85400 + 1708 = 87108
(c) 258 × 1008
Ans:-
258 x 1008 = 258 x (1000 + 8)
= 258 x 1000 + 258 x 8 [Using distributive property]
= 258000 + 2064 = 260064
(d) 1005 × 168
Ans:-
1005 x 168 = (1000 + 5) x 168
= 1000 x 168 + 5 x 168 [Using distributive property]
= 168000 + 840 = 168840
NCERT Solutions for Class 6 Maths Chapter 2 exercise 2.2 Question 5
5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If petrol costs ₹ 44 per litre, how much did he spend in all on petrol?
Ans:-
Petrol filled on Monday = 40 litres
Cost of petrol = ₹44 per litre
Petrol filled on Tuesday = 50 litre
Cost of petrol = ₹44 pet litre
∴ Total money spent in all
= ₹(40 x 44 + 50 x 44)
= ₹(40 + 50) x 44 = ₹90 x 44 = ₹3960
Exercise 2.2 class 6 Question 6
6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ₹ 45 per litre, how much money is due to the vendor per day?
Ans:-
Milk supplied in the morning = 32 litres
Cost of milk = ₹15 per litre
Milk supplied in the evening = 68 litres
Cost of milk = ₹15 per litre
Class 6 Exercise 2.2 Question 7
7. Match the following:
(i) 425 × 136 = 425 × (6 + 30 + 100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition.
Ans:-
(i) ↔ (c), (ii) ↔ (a) and (iii) ↔ (b)
Key Points
Some important key points in NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.2
- All natural numbers are whole numbers.
- All whole numbers, except 0, are natural numbers.
- Properties of Whole numbers:
- Whole numbers are closed under addition and also under multiplication.
- Whole numbers are not closed under subtraction and under division.
- Division of a whole number by 0 is not defined.
- Addition and multiplication are commutative for whole numbers.
Which is the smallest whole numbers
Zero is the smallest whole number.
Which is the biggest whole number?
We can’t find the greatest whole number. so we can say that infinity is the biggest whole number.
Is zero a whole number?
The whole numbers are the numbers 0, 1, 2, 3, 4, and so on. Negative numbers are not considered whole numbers. All natural numbers are whole numbers, but all whole numbers are not natural numbers since zero is a whole number but not a natural number.
Is Pi a real number?
Pi is an irrational number, which is not a real number that cannot be expressed by a simple fraction, pi value is 3.14 or 22/7.
Students are advised to read class 6 NCERT books. You can also download the NCERT book pdf only for Class 6 maths chapter 2.
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