Here at mentorathome we provide NCERT solutions for class 6 maths chapter 1 exercise 1.3 PDF. NCERT Class 6 maths chapter 1 Knowing our number exercise 1.3 deals with the concept of estimation. We provide NCERT Solutions for class 6 for all subjects. NCERT Solutions are designed by our well-experienced teachers.

It is very important to know the idea of estimation. Many time the concept of estimation make our calculation easy and through it, we try to approach the estimated answer. We provide NCERT solutions step-by-step explanations that are students easily grasp.

If you Want to check NCERT Solution for class 6 maths of other chapters select it below.

• Chapter 1 Knowing our Numbers
• Chapter 2 Whole Numbers
• Chapter 3 Playing With Numbers
• Chapter 4 Basic Geometrical Ideas
• Chapter 5 Understanding Elementary Shapes
• Chapter 6 Integers
• Chapter 7 Fractions
• Chapter 8 Decimals
• Chapter 9 Data Handling
• Chapter 10 Mensuration
• Chapter 11 Algebra
• Chapter 12 Ratio And Proportion
• Chapter 13 Introduction To Symmetry
• Chapter 14 Practical Geometry

## NCERT Solutions For Class 6 Maths Chapter 1 Exercise 1.3

Here we provide NCERT Class 6 maths Chapter 1 solutions/ question and answer.

Class 6 Maths exercise 1.3 Solutions Q1
Q.1. Estimate each of the following using general rules:
(a) 730 + 998 (b) 796 – 314 (c) 12904 + 2888 (d) 28292 – 21496
Make ten more such examples of addition, subtraction and estimation of their outcome.

(a) 730 + 998
Ans:-
Rounding off 730 nearest to hundreds = 700
Rounding off 998 nearest to hundreds = 1,000
∴ 730 + 998 = 700 + 1000 = 1700

(b) 796 – 314
Ans:-
Rounding off 796 nearest to hundreds = 800
Rounding off 314 nearest to hundreds = 300
∴ 796 – 314 = 800 – 300 = 500

(c) 12904 + 2888
Ans:-
Rounding off 12,904 nearest to thousands = 13000
Rounding off 2888 nearest to thousands = 3000
∴ 12,904 + 2,888 = 13000 + 3000 = 16000

(d) 28292 – 21496
Ans:-
Rounding off 28,292 nearest to thousands = 28,000
Rounding off 21,496 nearest to thousands = 21,000
∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000

Ten more such examples are:-
(i) 6440 – 2972 = 6000 – 3000 = 3000
(ii) 6393 – 3774 = 6000 – 4000 = 2000
(iii) 1110 – 1292 = 1000 – 1000 = 0
(iv) 1927 + 3185 = 2000 + 3,000 = 5,000
(v) 3258 – 1698 = 3000 – 2000 = 1,000
(vi) 8735 + 6232 = 9000 + 6000 = 15,000
(vii) 3731 + 1300 = 4000 + 1000 = 5000
(viii) 330 + 280 = 300 + 300 = 600
(ix) 1210 + 2365 = 1200 + 2400 = 3600
(x) 9854 – 6385 = 10,000 – 6000 = 4,000

Class 6 Maths exercise 1.3 Solutions Q2
Q. 2. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a) 439 + 334 + 4317 (b) 108734 – 47599 (c) 8325 – 491 (d) 489348 – 48365
Make four more such examples.

(a) 439 + 334 + 4317
Ans:-
(i) Rounding off to nearest hundreds
439 + 334 + 4,317 = 400 + 300 + 4300 = 5,000
(ii) Rounding off to nearest tens
439 + 334 + 4317 = 440 + 330 + 4320 = 5090.

(b) 108734 – 47599
Ans:-
(i) Rounding off to nearest hundreds
1,08,734 – 47,599 = 1,08,700 – 47,600 = 61,100
(ii) Rounding off to nearest tens
1,08,734 – 47,599 = 1,08,730 – 47,600 = 61,130.

(c) 8325 – 491
Ans:-
(i) Rounding off to nearest hundreds
8325 – 491 = 8300 – 500 = 7800
(ii) Rounding off to nearest tens
8325 – 491 = 8330 – 490 = 7840.

(d) 489348 – 48365
Ans:-
(i) Rounding off to nearest hundreds
4,89,348 – 48,365 = 4,89,300 – 48,400 = 4,40,900
(ii) Rounding off to nearest tens
4,89,348 – 48,365 = 4,89,350 – 48,370 = 4,40,980

Four more such examples are:-
(1) 4853 + 662
Ans:-
(i) Rounding off to nearest hundreds
4853 + 662 = 4900 + 700 =5600
(ii) Rounding off to nearest tens
4853 + 662 = 4850 + 660 =5510
(2) 8246 – 6312
Ans:-
(i) Rounding off to nearest hundreds
8246 – 6312 = 8200 – 6300 = 1900
(ii) Rounding off to nearest tens
8246 – 6312 = 8250 – 6310 = 1940
(3) 6653 – 8265
Ans:-
(i) Rounding off to nearest hundreds
6653 + 8265 = 6700 + 8300 = 15000
(ii) Rounding off to nearest tens
6653 + 8265 = 6650 + 8270 = 14920
(4) 384 + 562
Ans:-
(i) Rounding off to nearest hundreds
384 + 562 = 400 + 600 = 1000
(ii) Rounding off to nearest tens
384 + 562 = 380 + 560 = 940

Class 6 Maths exercise 1.3 Solutions Q3
Q.3.Estimate the following products using general rule:
(a) 578 x 161
(b)5281 x 3491
(c) 1291 x 592
(d) 9250 x 29
Make four more such examples.

(a) 578 x 161
Ans:-
Rounding off by general rule
578 and 161 rounded off to 600 and 200
respectively = 600 x 200 = 1,20,000
(b) 5281 x 3491
Ans:-
Rounding off by general rule
5281 and 3491 rounded off to 5000 and 3500
respectively = 5000 x 3500 = 1,75,00,000
(c) 1291 x 592
Ans:-
Rounding off by general rule
1291 and 592 rounded off to 1300 and 600
respectively  = 1300 x 600 = 7,80,000
(d) 9250 x 29
Rounding off by general rule
9250 and 29 rounded off to 9000 and 30
respectively = 9000 x 30 = 2,70,000

Four more such examples are:-
(i) 383 x 1061
Ans:-
Rounding off by general rule
383 and 1061 rounded off to 400 and 1000
respectively = 400 x 1000 = 4,00,000
(ii) 693 x 982
Ans:-
Rounding off by general rule
700 and 1000 rounded off to 700 and 1000
respectively = 700 x 1000 = 7,00,000
(iii) 3692 x 49
Ans:-
Rounding off by general rule
3692 and 49 rounded off to 4000 and 50
respectively = 4000 x 50 = 2,00,000
(iv) 8731 x 1535
Ans:-
Rounding off by general rule
8731 and 1535 rounded off to 9000 and 1500
respectively = 9000 x 1500 = 1,35,00,000

### What we learn

In NCERT Solutions For Class 6 Maths Chapter 1 Ex 1.3 we learn about Estimation, Rounding off, and approximation. We also do multiplication addition and subtraction questions with the help of Estimation and round off.

We recommend you to read Class 6 Maths NCERT Books. You can also download class 6 ncert books for other subjects also.

### What is Estimation?

Estimation is the process of finding approximation.

### What is Rounding off?

Rounding means replacing a number with the approximate value which is near that number.

### How do we round off a number to the nearest 10

rounding off nearest to 10 means approximate last two digits of the given number in the multiple of ten. eg-
consider 2 no 12 and 19. If we plot these numbers in number line we find that both no. 12 and 19 lie between 10 and 20. Also, 12 is near to 10 while 19 is near 20. So round off 12 is 10 nearest to tens while round off 19 is 20 nearest to tens. so we can say that rounding of 10 means that we wish to round off the last two-digit number by two method

### What are the types of rounding off?

There are two types of rounding off.
1. round-up 2. Rounding down.
If the number at tens places is 5 or more than 5 (6,7,8,9), then the number is rounding up otherwise rounding down. In a similar way, we round off hundred, thousand, and so on. In the round of hundred, we round off the last 3 digits and so on.

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