NCERT Solutions For Class 6 Maths Chapter 8 Decimals free pdf

NCERT Solutions For Class 6 Maths Chapter 8 Decimals

Here at MentorAtHome, We provide NCERT Solutions For Class 6 Maths Chapter 8 Decimals. NCERT solutions help students to improve their performance, and attain better results. In NCERT Solutions Class 6 Maths Chapter 8 there is 6 exercise.

NCERT Solutions For Class 6 Maths Chapter 8 decimal, will discuss Every fraction with denominator 10 can be written in decimal notation and vice-versa. NCERT Solutions For Class 6 Maths Chapter is important for basic understanding.

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.1

Class 6th Maths Chapter 8 Solutions ex 8.1

Q.1. Write the following numbers in the given table.

Hundreds	Tens	Ones	Tenths
(100)	(10)	(1)	(1/10)

Ans:-

Rows	Hundreds	Tens	Ones	Tenths
a	0	3	1	2
b	1	1	0	4

Q.2. Write the following decimals in the place value table.
(a) 19.4
(b) 0.3
(c) 10.6
(d) 205.9
Ans:-

	Hundreds	Tens	Ones	Tenths
19.4	0	1	9	4
0.3	0	0	0	3
10.6	0	1	0	6
205.9	2	0	5	9

Q.3. Write each of the following as decimals:
(a) Seven-tenths
(b) Two tens and nine-tenths
(c) Fourteen point six
(d) One hundred and two ones
(e) Six hundred point eight
Ans:-
(a) Seven-tenths is 7 / 10 = 0.7
(b) two tens and nine tenths is 20 + 9 / 10 = 20.9
(c) Fourteen point six = 14.6
(d) One hundred and two ones
= 1 x 100 + 2 x 1 = 100 + 2 = 102
(e) six hundred point eight is 600.8

Q.4. Write each of the following as decimals:
(a) 5 / 10
(b) 3 + 7 / 10
(c) 200 + 60 + 5 + 1 / 10
(d) 70 + 8 / 10
(e) 88 / 10

(g) 3 / 2
(h) 2 / 5
(i) 12 / 5

Ans:-
(a) 5 / 10
= 0.5
(b) 3 + 7 / 10
= 3 + 0.7
= 3.7
(c) 200 + 60 + 5 + 1 / 10
= 265 + 0.1
= 265.1
(d) 70 + 8 / 10
= 70 + 0.8
= 70.8
(e) 88 / 10
= 80 / 10 + 8 / 10
= 8 + 0.8
= 8.8
(f) 42 / 10
= 4.2
(g) 3 / 2
Nominators and denominators are multiplied by = 5
3 x 5 / 2 x 5
= 15 / 10
=1. 5
(h) 2 / 5
Nominators and denominators are multiplied by = 2
2 x 2 / 5 / 2
= 4 / 10
= 0.4
(i) 12 / 5
Nominators and denominators are multiplied by = 2
12 x 2 / 5 x 2
=24 / 10
=2.4
(j) 18 / 5
Nominators and denominators are multiplied by = 2
18 x 2 / 5 x 2
= 36 / 10
=3.6
(k) 9 / 2
Nominators and denominators are multiplied by = 5
9 x 5 / 2 x 5
= 45 / 10
= 4.5

Q.5. Write the following decimals as fractions. Reduce the fraction to lowest form.
(a) 0.6
(b) 2.5
(c) 1.0
(d) 3.8
(e) 13.7
(f) 21.2
(g) 6.4
Ans:-

6. Express the following as cm using decimals.
(a) 2 mm
(b) 30 mm
(c) 116 mm
(d) 4 cm 2 mm
(e) 162 mm
(f) 83 mm
Ans:-
We know that 1 cm = 10 mm and 1 mm = 1 / 10 cm

7. Between which two whole numbers on the number line are the given numbers lie?

Which of these whole numbers is nearer the number?

(a) 0.8
(b) 5.1
(c) 2.6
(d) 6.4
(e) 9.1
(f) 4.9
Ans:-
(a) 0.8 lies between the whole numbers 0 and 1.
(b) 5.1 lies between the whole numbers 5 and 6.
(c) 2.6 lies between the whole numbers 2 and 3
(d) 6.4 lies between 6 and 7 so.(6.4 is nearer to 6)
(e) 9.1 lies between 9 and 10 so.(9.1 is nearer to 9)
(f) 4.9 lies between the whole numbers 4 and 5.

8. Show the following numbers on the number line.
(a) 0.2
(b) 1.9
(c) 1.1
(d) 2.5
Ans:-

Q.9. Write the decimal number represented by the points A, B, C, and D on the given number line.

Ans:-
(a) Point A represents 0.8 cm
(b) Point B represents 1.3 cm
(c) Point C represents 2.2 cm
(d) Point D represents 2.9 cm

Q.10. (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
(b) The length of a young gram plant is 65 mm. Express its length in cm.
Ans:-
(a) The length of Ramesh notebook is 9 cm 5 mm
1 mm = 1 / 10 cm
5mm = 5 / 10 cm
The length in cm is [(9 + 5 / 10)] cm
= 9.5 cm
(b) The length of a gram plant is 65 mm
1 mm = 1 / 10 cm
Hence, the length in cm is 65 / 10
= 6.5 cm

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.2

NCERT Class 6 Maths Chapter 8 Solutions ex 8.2

Q.1. Complete the table with the help of these boxes and use decimals to write the number.

Ans:-

Rows	Ones	Tenths	Hundreds	Numbers
(a)	0	2	6	0.26
(b)	1	3	8	1.38
(c)	1	2	8	1.28

Q.2. Write the numbers given in the following place value table in decimal form.

Rows	Hundreds	Tens	Ones	tenths	Hundredths	Thousandths
	100	10	1	1/10	1/100	1/1000
(a)	0	0	3	2	5	0
(b)	1	0	2	6	3	0
(c)	0	3	0	0	2	5
(d)	2	1	1	9	0	2
(e)	0	1	2	2	4	1

Ans:-
(a) 0 Hundreds + 0 Tens + 3 Ones + 2 Tenths + 5 Hundredths + 0 Thousandths
 0 + 0 + 3 + 2 / 10 + 5 / 100 + 0
= 3 + 0.2 + 0.05
= 3.25
(b) 1 Hundreds + 0 Tens + 2 Ones + 6 Tenths + 3 Hundredths + 0 Thousandths
100 + 0 + 2 + 6 / 10 + 3 / 100 + 0
= 102 + 0.6 + 0.03
= 102.63
(c) 0 Hundreds + 3 Tens + 0 Ones + 0 Tenths + 2 Hundredths + 5 Thousandths
0 + 30 + 0 + 0 + 2 / 100 + 5 / 1000
= 30 + 0.02 + 0.005
= 30.025
(d) 2 Hundreds + 1 Tens + 1 Ones + 9 Tenths + 0 Hundredths + 2 Thousandths
200 + 10 + 1 + 9 / 10 + 0 + 2 / 1000
= 211 + 0.9 + 0.002
= 211.902
(e) 0 Hundreds + 1 Tens + 2 Ones + 2 Tenths + 4 Hundredths + 1 Thousandths
0 + 10 + 2 + 2 / 10 + 4 / 100 + 1 / 1000
= 12 + 0.2 + 0.04 + 0.001
= 12.241

Q.3. Write the following decimals in the place value table.
(a) 0.29 (b) 2.08
(c) 19.60 (d) 148.32
(e) 200.812
Ans:-
(a) 0.29
=0 + 0.2 + 0.09
=0 + 2 / 10 + 9 / 100
0 Ones + 2 Tenths + 9 Hundredths
(b) 2.08
= 2 + 0.0 + 0.08
= 2 + 0 / 10 + 8 / 100
2 Ones + 0 Tenths + 8 Hundredths
(c) 19.60
= 10 + 9 + 0.6 + 0.00
= 10 + 9 + 6 / 10 + 0 / 100
1 Tens + 9 Ones + 6 Tenths + 0 Hundredths
(d) 148.32
= 100 + 40 + 8 + 0.3 + 0.02
= 100 + 40 + 8 + 3 / 10 + 2 / 100
1 Hundred + 4 Tens + 8 Ones + 3 Tenths + 2 Hundred
(e) 200.812
= 200 + 0.8 + 0.01 + 0.002
=200 + 8 / 10 + 1 / 100 + 2 / 1000
2 Hundreds + 8 Tenths + 1 Hundredth + 2 Thousandths

	Hundreds	Tens	Ones	Tenths	Hundredths	Thousandths
(a)	0	0	0	2	9	0
(b)	0	0	2	0	8	0
(c)	0	1	9	6	0	0
(d)	1	4	8	3	2	0
(e)	2	0	0	8	1	0

Q.4. Write each of the following as decimals.
(a) 20 + 9 + 4 / 10 + 1 / 100
(b) 137 + 5 / 100
(c) 7 / 10 + 6 / 100 + 4 / 1000
(d) 23 + 2 / 10 + 6 / 1000
(e) 700 + 20 + 5 + 9 / 100
Ans:-
(a) 20 + 9 + 4 / 10 + 1 / 100
= 29 + 0.4 + 0.01
= 29.41
(b) 137 + 5 / 100
= 137 + 0.05
= 137.05
(c) 7 / 10 + 6 / 100 + 4 / 1000
= 0.7 + 0.06 + 0.004
=0.764
(d) 23 + 2 / 10 + 6 / 1000
= 23 + 0.2 + 0.006
= 23.206
(e) 700 + 20 + 5 + 9 / 100
= 725 + 0.09
= 725.09

Q.5. Write each of the following decimals in words.
(a) 0.03 (b) 1.20
(c) 108.56 (d) 10. 07
(e) 0.032 (f) 5.008
Ans:-
(a) 0.03 = Zero point zero three
(b) 1.20 = One point two zero
(c) 108.56 = One hundred eight point fifty-six
(d) 10.07 = Ten point zero seven
(e) 0.032 = Zero point zero three two
(f) 5.008 = Five point zero zero eight

6. Between which two numbers in tenths place on the number line does each of the given number lie?(a) 0.60 (b) 0.45
(c) 0.19 (d) 0.66
(e) 0.92 (f) 0.57
Ans:-
(a) 0.06 lies between 0 and 0.1
(b) 0.45 lies between 0.4 and 0.5
(c) 0.19 lies between 0.1 and 0.2
(d) 0.66 lies between 0.6 and 0.7
(e) 0.92 lies between 0.9 and 1.0
(f) 0.57 lies between 0.5 and 0.6

7. Write as fractions in lowest terms.
(a) 0.60 (b) 0.05
(c) 0.75 (d) 0.18
(e) 0.25 (f) 0.125
(g) 0.066
Ans:-
(a) 0.60 = 60 / 100
= 6 / 10 = 3 / 5
(b) 0.05 = 5 / 100
= 1 / 20
(c) 0.75 = 75 / 100
= 3 / 4
(d) 0.18 = 18 / 100
= 9 / 50
(e) 0.25 = 25 / 100
= 1 / 4
(f) 0.125 = 125 / 1000
= 1 / 8
(g) 0.066 = 66 / 1000
= 33 / 500

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.3

Ch 8 Class 6 Maths Solutions ex 8.3

Q.1. Which is greater?
(a) 0.3 or 0.4 (b) 0.07 or 0.02
(c) 3 or 0.8 (d) 0.5 or 0.05
(e) 1.23 or 1.2 (f) 0.099 or 0.19
(g) 1.5 or 1.50 (h) 1.431 or 1.490
(i) 3.3 or 3.300 (j) 5.64 or 5.603
Ans:-
(a) 0.3 or 0.4
= 3 / 10 and 4 / 10
denominator are same
∴ 3 < 4
∴ 0.3 < 0.4
(b) 0.07 or 0.02
= 7 / 100 and 2 / 100
denominator are same
∴ 7 > 2
∴ 0.07 > 0.02
(c) 3 or 0.8
3 is greater than 0 and 0 > 0.8
∴ 3 is greater than 0.8.
∴ 3 > 0.8
(d) 0.5 or 0.05
50 / 100 and 5 / 100
denominator are same
∴ 50 > 5
∴ 0.5 > 0.05
(e) 1.23 or 1.2
123 / 100 and 120 / 100
denominator are same
∴ 123 > 120
∴ 1.23 > 1.2
(f) 0.099 or 0.19
99 / 1000 and 190 / 1000
denominator are same
∴ 99 < 190
∴ 0.099 < 0.19
(g) 1.5 or 1.50
150 / 100 and 150 / 100
denominator are same
∴ 150 = 150
∴ 1.5 =1.50
(h) 1.431 or 1.490
1431 / 1000 and 1490 / 1000
denominator are same
∴ 1431 < 1490
∴ 1.431 < 1.490
(i) 3.3 or 3.300
3300 / 1000 and 3300 / 1000
denominator are same
∴ 3300 = 3300
∴ 3.3 = 3.300
(j) 5.64 or 5.603
5640 / 1000 and 5603 / 1000
denominator are same
∴ 5640 > 5603
∴ 5.64 > 5.603

Q.2. Make five more examples and find the greater number from them.
Ans:-
(a) 31.54 or 31.5
3155 / 100 and 3150 / 100
3155 > 3150
∴ 3.54 > 31.5
(b) 1 or 0.99
100 / 100 and 99 / 100
100 > 99
∴ 1 > 0.99
(c) 1.09 or 1.091
1090 / 1000 and 1091 / 1000
∴ 1090 <1091
∴ 1.09 < 1.091
(d) 2 or 1.99
200 / 100 and 199
∴ 200 > 199
∴ 2 > 1.99
(e) 2.07 or 2.083
2070 / 1000 and 2083
∴ 2070 <2083
∴ 2.07 < 2.083

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.4

NCERT Class 6 Maths Chapter 8 Solutions Ex 8.4

Q.1. Express as rupees using decimals.
(a) 5 paise (b) 75 paise
(c) 20 paise (d) 50 rupees 90 paise
(e) 725 paise
Ans:-
We know that there are 1 rupee = 100 paise
(a) 5 paise
100 paise =1 rupee
1 paise = 1 / 100 rs
5 paise =1 x 5 / 100
= 0.05 Rupess
(b) 75 paise
100 paise =1 rupee
1 paise = 1 / 100 rs
75 paise =1 x 75 / 100
= 0.75 Rupess
(c) 20 paise
100 paise =1 rupee
1 paise = 1 / 100 rs
20 paise =1 x 20 / 100
= 0.20 Rupess
(d) 50 rupees 90 paise
= [(50 + 90 / 100)] rupees
= 50.90 Rupees
(e) 725 paise
100 paise =1 rupee
1 paise = 1 / 100 rs
725 paise =1 x 725 / 100
= 7.25 Rupess

Q.2. Express as meters using decimals.
(a) 15 cm (b) 6 cm
(c) 2 m 45 cm (d) 9 m 7 cm
(e) 419 cm
Ans:-
We know that there are 1 meter = 100 cm
(a) 15 cm
100 cm = 1 meter
1 cm = 1 / 100 m
15 cm 1 x 15 / 100
= 0.15 m.
(b) 6 cm
100 cm = 1 meter
1 cm = 1 / 100 m
6 cm 1 x 6 / 100
= 0.06 m.
(c) 2 m 45 cm
=[(2 + 45 / 100)] m
= 2.45 m
(d) 9 m 7 cm
=[(9 + 7 / 100)] m
= 9.07 m
(e) 419 cm
100 cm = 1 meter
1 cm = 1 / 100 m
419 cm 1 x 419 / 100
= 4.19 m.

Q.3. Express as cm using decimals
(a) 5 mm (b) 60 mm
(c) 164 mm (d) 9 cm 8 mm
(e) 93 mm
Ans:-
We know that there are 10 mm in 1 cm
(a) 5 mm
10 mm = 1 cm
1 mm = 1 / 10 cm
5 mm =1 x 5 / 10
= 0.5 cm
(b) 60 mm
10 mm = 1 cm
1 mm = 1 / 10 cm
60 mm =1 x 60 / 10
= 6 cm
(c) 164 mm
10 mm = 1 cm
1 mm = 1 / 10 cm
164 mm =1 x 164 / 10
= 16.4 cm
(d) 9 cm 8 mm
= [(9 + 8 / 10)] cm
= 9.8 cm
(e) 93 mm
10 mm = 1 cm
1 mm = 1 / 10 cm
93 mm =1 x 93 / 10
= 9.3 cm

Q.4. Express as km using decimals.
(a) 8 m (b) 88 m
(c) 8888 m (d) 70 km 5 m
Ans:-
We know that there are 1000 meters in 1 km
(a) 8 m
1000 m = 1 km
1 m = 1 / 1000 km
8 m = 1 x 8 / 1000
= 0.008 km
(b) 88 m
1000 m = 1 km
1 m = 1 / 1000 km
88 mm = 1 x 88 / 1000
= 0.088 km
(c) 8888 m
1000 m = 1 km
1 m = 1 / 1000 km
8888 mm = 1 x 8888 / 1000
= 8.888 km
(d) 70 km 5 m
= [(70 + 5 / 1000)] km
= 70.005 km

Q.5. Express as kg using decimals.
(a) 2 g (b) 100 g
(c) 3750 g (d) 5 kg 8 g
(e) 26 kg 50 g
Ans:-
We know that there are 1000 grams in 1 kg
(a) 2 g
1000 g = 1 kg
1 g = 1 / 1000 kg
2 g = 1 x 2 / 1000
= 0.002 kg
(b) 100 g
1000 g = 1 kg
1 g = 1 / 1000 kg
100 g = 1 x 100 / 1000
= 0.1 kg
(c) 3750 g
1000 g = 1 kg
1 g = 1 / 1000 kg
3750 g = 1 x 3750 / 1000
= 3.750 kg
(d) 5 kg 8 g
= [(5 + 8 / 1000)] kg
= 5.008 kg
(e) 26 kg 50 g
= [(26 + 50 / 1000)] kg
= 26.050 kg

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.5

Class 6th Maths Chapter 8 solutions Ex 8.5

Q.1. Find the sum in each of the following:
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38
Ans:-
(a) Sum of 0.007 + 8.5 + 30.08

(b) Sum of 15 + 0.632 + 13.8

(c) Sum of 27.076 + 0.55 + 0.004

(d) Sum of 25.65 + 9.005 + 3.7

(e) Sum of 0.75 + 10.425 + 2

(f) Sum of 280.69 + 25.2 + 38

Q.2. Rashid spent ₹ 35.75 on Maths book and ₹ 32.60 on Science book. Find the total amount spent by Rashid.
Ans:-
Cost of Maths book = ₹ 35.75
Cost of Science book = ₹ 32.60
The total amount spent by Rashid is

Q.3. Radhika’s mother gave her ₹ 10.50 and her father gave her ₹ 15.80, find the total amount given to Radhika by the parents.
Ans:-
The amount is given by Radhika’s mother = ₹ 10.50
The amount is given by Radhika’s father = ₹ 15.80
The total amount given by her parents

Q.4. Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Ans:-
Cloth of shirt = 3 m 20 cm
Cloth of trouser = 2 m 5 cm
The total length of cloth is

Q.5. Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?
Ans:-
Distance walked by Naresh in the morning = 2 km 35 m
= [(2 + 35 /1000)] km
= 2.035 km.
Distance walked by him in the evening = 1 km 7 m
= [(1 + 7 / 1000)] km
= 1.007 km
∴ Total distance walked by him in all

Q.6. Sunita traveled 15 km 268 m by bus, 7 km 7 m by car, and 500 m on foot in order to reach her school. How far is her school from her residence?
Ans:-
Distance travelled by Sunita by bus= 15 km 268 m
= [(15 + 268 / 1000)]
= 15.268 km
Distance travelled by her by car= 7 km 7 m
= [(7 + 7 / 1000)] km
= 7.007 km
Distance walked by Sunita = 500 m
= 500 / 1000
= 0.500 km
Total distance of school from her residence is

Q.7. Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
Ans:-
Weight of rice = 5 kg 400 g
= [(5 + 400 / 1000)] kg
= 5.400 kg
Weight of sugar = 2 kg 20 g
= [(2 + 20 / 1000)] kg
= 2.020 kg
Weight of flour = 10 kg 850 g
= [(10 + 850 / 1000)] kg
= 10.850 kg
Total weight of his purchases is

NCERT Solutions For Class 6 Maths Chapter 8 Decimals Exercises 8.6

Ch 8 Class 6 Maths Solutions Ex 8.6

Q.1. Subtract:
(a) ₹ 18.25 from ₹ 20.75
(b) 202.54 m from 250 m
(c) ₹ 5.36 from ₹ 8.40
(d) 2.051 km from 5.206 km
(e) 0.314 kg from 2.107 kg
Ans:-
(a) ₹ 20.75 – ₹ 18.75

(b) 250 m – 202.54 m

(c) ₹ 8.40 – ₹ 5.36

(d) 5.206 km – 2.051 km

(e) 2.107 kg – 0.314 kg

Q.2. Find the value of:
(a) 9.756 – 6.28
(b) 21.05 – 15.27
(c) 18.5 – 6.79
(d) 11.6 – 9.847
Ans:-
(a) 9.756 – 6.28

(b) 21.05 – 15.27

(c) 18.5 – 6.79

(d) 11.6 – 9.847

Q.3. Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?
Ans:-
Cost of book = ₹35.65
Money paid by him to the shopkeeper = ₹50
∴ Money got back by him

Q.4. Rani had ₹ 18.50. She bought one ice cream for ₹ 11.75. How much money does she have now?
Ans:-
Money with Rani = ₹ 18.50
Price of an ice cream = ₹ 11.75
money left with rani is

Q.5. Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?
Ans:-
Length of cloth = 20 m 5 cm = 20.05 m
Length of cloth to make a curtain = 4 m 50 cm = 4.50 m
Length of cloth left with her

Q.6. Namita travels 20 km 50 m every day. Out of this, she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Ans:-
Distance traveled by Namita = 20 km 50 m or 20.050 km
Distance traveled by bus = 10 km 200 m or 10.200 km
Distance traveled by auto =

∴ Namita traveled 9.850 km by auto

Q.7. Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?
Ans:-
Weight of vegetables bought by Aakash = 10 kg
Weight of onions bought by him = 3 kg 500 g = 3.500 kg
and weight of tomatoes bought by him = 2 kg 75 g = 2.075 kg
∴ Weight of potatoes = Weight of vegetable – (weight of onions + weight of tomatoes) 10.000 – (3.500 + 2.075)

∴ 4.425 kg is the weight of the potatoes

Class 6 Science NCERT Notes	Class 6 Complete Study Material
NCERT Solutions for Class 6 Science	Class 6 Maths Chapter 6 Solutions

NCERT Solutions For Class 6 Maths Chapter 8 decimal are based on NCERT Books. You can download ncert book for class 6 maths chapter 8. Ch 8 class 6 maths solutions are designed by our subject expert team.

What We Learn?

1. To understand the parts of one whole (i.e. a unit) we represent a unit by a block. One
   block divided into 10 equal parts means each part is1/10(one-tenth) of a unit. It can
   be written as 0.1 in decimal notation. The dot represents the decimal point and it
   comes between the units place and the tenths place.
2. Every fraction with denominator 10 can be written in decimal notation and vice-versa.
3. One block divided into 100 equal parts means each part is 1/100(one-hundredth) of
   a unit. It can be written as 0.01 in decimal notation.
4. Every fraction with denominator 100 can be written in decimal notation and
   vice-versa.
5. In the place value table, as we go from left to the right, the multiplying factor becomes 1/10 of the previous factor. The place value table can be further extended from hundredths to 1/10 of hundredths i.e. thousandths 1/1000 which is written as 0.001 in decimal notation.

6. All decimals can also be represented on a number line.
7. Every decimal can be written as a fraction.
8. Any two decimal numbers can be compared among themselves. The comparison can
   start with the whole part. If the whole parts are equal then the tenth parts can be
   compared and so on.
9. Decimals are used in many ways in our lives. For example, in representing units of
   money, length and weight.